Em tham khảo nha :
\(\begin{array}{l}
a)\\
{n_{C{O_2}}} = \dfrac{{2,24}}{{22,4}} = 0,1mol\\
{n_{NaOH}} = 0,1 \times 2 = 0,2mol\\
T = \dfrac{{{n_{NaOH}}}}{{{n_{C{O_2}}}}} = \dfrac{{0,2}}{{0,1}} = 1\\
\Rightarrow\text{Phản ứng tạo ra 1 muối :} N{a_2}C{O_3}\\
2NaOH + C{O_2} \to N{a_2}C{O_3} + {H_2}O\\
b)\\
{n_{N{a_2}C{O_3}}} = {n_{C{O_2}}} = 0,1mol\\
{C_{{M_{N{a_2}C{O_3}}}}} = \dfrac{{0,1}}{{0,2}} = 0,5M
\end{array}\)