1)
Rắn màu vàng là \(S\)
\({n_S} = \frac{{0,64}}{{32}} = 0,02{\text{ mol}}\)
Bảo toàn e:
\(2{n_{Zn}} = 6{n_S} \to {n_{Zn}} = 3{n_S} = 0,02.3 = 0,06{\text{ mol = }}{{\text{n}}_{ZnS{O_4}}}\)
\( \to m = {m_{Zn}} = 0,06.65 = 3,9{\text{ }}gam\)
\({m_{ZnS{O_4}}} = 0,06.(65 + 96) = 9,66{\text{ gam}}\)
2)
Ta có:
\({n_{S{O_2}}} = \frac{{6,72}}{{22,4}} = 0,3{\text{ mol;}}{{\text{n}}_S} = \frac{{1,6}}{{32}} = 0,05{\text{ mol}}\)
Bảo toàn e:
\(2{n_{Mg}} = 2{n_{S{O_2}}} + 6{n_S} = 0,3.2 + 0,05.6 = 0,9{\text{ mol}}\)
\( \to {n_{Mg}} = 0,45{\text{ mol}} \to {\text{m = }}{{\text{m}}_{Mg}} = 0,45.24 = 10,8{\text{ gam}}\)