1)
Phản ứng xảy ra:
\(3{C_2}{H_2}\xrightarrow{{{t^o},xt}}{C_6}{H_6}\)
Ta có:
\({n_{{C_2}{H_2}}} = \frac{{5,6}}{{22,4}} = 0,25{\text{ mol}}\)
\( \to {n_{{C_2}{H_2}{\text{ phản ứng}}}} = 0,25.60\% = 0,15{\text{ mol}}\)
\( \to {n_{{C_6}{H_6}}} = \frac{1}{3}{n_{{C_2}{H_2}{\text{ phản ứng}}}} = 0,05{\text{ mol}}\)
\( \to {m_{{C_6}{H_6}}} = 0,05.(12.6 + 6) = 3,9{\text{ gam}}\)
2)
Phản ứng xảy ra:
\({C_2}{H_2} + 2B{r_2}\xrightarrow{{}}{C_2}{H_2}B{r_4}\)
Ta có:
\({n_{{C_2}{H_2}}} = \frac{{2,24}}{{22,4}} = 0,1{\text{ mol}}\)
\( \to {n_{B{r_2}}} = 2{n_{{C_2}{H_2}}} = 0,2{\text{ mol}}\)
\( \to {m_{B{r_2}}} = 0,2.80.2 = 32{\text{ gam}}\)