Đáp án:
\(\begin{array}{l}
1.\\
R = \frac{{400\pi }}{3}\\
2.\\
a.\\
Q = 1000J\\
b.\\
\$ = 90000d\\
3.\\
{R_1} = 10\\
{R_2} = 30
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
1.\\
l = N2\pi r = 1000.2\pi 0,1 = 200\pi \\
R = \frac{{\rho l}}{s} = \frac{{0,{{4.10}^{ - 6}}.200\pi }}{{0,{{6.10}^{ - 6}}}} = \frac{{400\pi }}{3}\\
2.\\
a.\\
Q = Pt = 1000.1 = 1000J\\
b.\\
Q = Pt = 1000.3.30 = 90000Wh = 90kWh\\
\$ = Q.1000 = 90000d\\
3.\\
I = \frac{U}{{{R_1} + {R_2}}}\\
0,3 = \frac{{12}}{{{R_1} + {R_2}}}\\
{R_1} + {R_2} = 40\\
I' = \frac{U}{{R'}} = \frac{U}{{\frac{{{R_1}{R_2}}}{{{R_1} + {R_2}}}}}\\
1,6 = \frac{{12.40}}{{{R_1}{R_2}}}\\
{R_1} = 10\\
{R_2} = 30
\end{array}\)