Đáp án:
$\begin{array}{l}
a){\left( {0,125} \right)^3}{.8^3}\\
= {\left( {\dfrac{1}{8}} \right)^3}{.8^3}\\
= 1\\
b)2 - \left( { - \dfrac{3}{2}} \right) + \dfrac{{16}}{4}:\dfrac{1}{2}\\
= 2 + \dfrac{3}{2} + 4.2\\
= 2 + \dfrac{3}{2} + 8\\
= 10 + \dfrac{3}{2}\\
= \dfrac{{23}}{2}\\
c)\dfrac{{{3^5}.9}}{{{3^7}{{.2}^0}}} = \dfrac{{{3^5}{{.3}^2}}}{{{3^7}.1}} = 1\\
d)\dfrac{3}{2} - \dfrac{5}{6}:{\left( {\dfrac{1}{2}} \right)^2} + \sqrt 4 \\
= \dfrac{3}{2} - \dfrac{5}{6}{.2^2} + 2\\
= \dfrac{3}{2} - \dfrac{5}{6}.4 + 2\\
= \dfrac{3}{2} - \dfrac{{10}}{3} + 2\\
= \dfrac{{9 - 20 + 12}}{6}\\
= \dfrac{{12 - 11}}{6}\\
= \dfrac{1}{6}
\end{array}$
