Đáp án:
` a)`
` ( x+12)(-3x+9) = 0`
` =>` \(\left[ \begin{array}{l}x+12=0\\-3x+9=0\end{array} \right.\)
` =>` \(\left[ \begin{array}{l}x=-12\\-3x=-9\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=-12\\x=3\end{array} \right.\)
`b)`
` (x^2 +1)(x-5) = 0`
Ta có
` x^2 \geq 0`
` => x^2 + 1 \geq 1`
` => x^2 > 0`
` => x - 5 = 0`
` => x= 5`