+) $3(x+2) = 5(2x-3)$
=> $3x + 6 - 10x +15 = 0$
=> $-7x + 21=0$
=> $-7x = -21$
=>$ x = 3$
+)
$x(x-2) -3x +6 =0$
=> $ x(x-2) - 3(x-2) = 0$
=> $(x-3)(x-2) = 0$
=> \(\left[ \begin{array}{l}x-3=0\\x-2=0\end{array} \right.\)
=> \(\left[ \begin{array}{l}x=3\\x=2\end{array} \right.\)