1:(2x+1)(x-1) = 0
=>2x+1=0=>x=-1/2
x-1=0=>x=1
2:(3x-1)(2x-3)(x+5) = 0
=>3x-1=0=>x=1/3
2x-3=0=>x=3/2
x+5=-5
3x−15=2x(x-5)
⇔3(x−5)=2x(x−5)⇔3(x−5)=2x(x−5)
⇔3(x−5)−2x(x−5)=0⇔3(x−5)−2x(x−5)=0
⇔(3−2x)(x−5)=0⇔(3−2x)(x−5)=0
⇔[3−2x=0x−5=0⇔[x=1,5x=5
4:x2 – x = 0
=>x(2-1)=0
=>x=0