Đáp án:
Giải thích các bước giải:
bài 1
a)
$\dfrac{1}{3}$-$\dfrac{2}{6}$+$\dfrac{3}{9}$
= $\dfrac{1}{3}$-$\dfrac{1}{3}$+$\dfrac{1}{3}$
=$\dfrac{1}{3}$
b)
$\dfrac{-4}{12}$+$\dfrac{18}{45}$-$\dfrac{6}{9}$+$\dfrac{24}{30}$
= $\dfrac{-1}{3}$+$\dfrac{2}{5}$-$\dfrac{2}{3}$+$\dfrac{4}{5}$
= $\dfrac{-1}{3}$+$\dfrac{2}{3}$+$\dfrac{2}{5}$+$\dfrac{4}{5}$
= $\dfrac{1}{3}$+$\dfrac{6}{5}$
= $\dfrac{23}{15}$