Đáp án:
1,
Oxit bazo: \({K_2}O,BaO,CaO,CuO\).
Bazo tương ứng: \(KOH,Ba{(OH)_2},Ca{(OH)_2},Cu{(OH)_2}\)
Oxit axit: \(S{O_3},{N_2}{O_5}\).
Axit tương ứng: \({H_2}S{O_{4,}}HN{O_3}\)
2,
\(\begin{array}{l}
2KCl{O_3} \to 2KCl + 3{O_2}\\
{n_{{O_2}}} = \dfrac{{16}}{{32}} = 0,5mol \to {n_{KCl{O_3}}} = \dfrac{2}{3}{n_{{O_2}}} = \dfrac{1}{3}mol\\
{m_{KCl{O_3}}} = 40,83g\\
{n_{{O_2}}} = \dfrac{{5,6}}{{22,4}} = 0,25mol \to {n_{KCl{O_3}}} = \dfrac{2}{3}{n_{{O_2}}} = \dfrac{1}{6}mol\\
{m_{KCl{O_3}}} = 20,42g
\end{array}\)