Đặt n CH4 = a(mol); n C2H4 = b(mol)
PTHH: CH4 +2O2 -to-> CO2 + 2H2O
(mol)___a_____2a_________a_______2a___
PTHH: C2H4 + 3O2 -to-> 2CO2 + 2H2O
(mol)___b________3b________2b______2b__
Theo đề bài ta có:
22,4(a+b) = 11,2
44(a+2b)=30,8
=> a=0,3;b=0,2
%V CH4 = (22,4.0,3)/11,2.100%=60%
=> %V C2H4 = 100-60=40%
V O2 = 22,4(2a+3b)=22,4(2.0,3+0,2.3)=26,88(l)