Đáp án:
\(\begin{array}{l}
A = \frac{1}{x}\\
B = \frac{{4x - 4}}{{5x + 30}}
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
a.DK:x \ne \left\{ { - \frac{3}{2};0} \right\}\\
A = \frac{{3x - x + 3}}{{x\left( {2x + 3} \right)}} = \frac{{2x + 3}}{{x\left( {2x + 3} \right)}} = \frac{1}{x}\\
b.DK:x \ne 1\\
B = \frac{{4\left( {x - 6} \right)}}{{5\left( {x - 1} \right)}}.\frac{{{{\left( {x - 1} \right)}^2}}}{{\left( {x - 6} \right)\left( {x + 6} \right)}}\\
= \frac{4}{5}.\frac{{x - 1}}{{x + 6}}\\
= \frac{{4x - 4}}{{5x + 30}}
\end{array}\)
