$1)\dfrac{x-2}{3-x} < 0$
$\text{ta có 2 trường hợp}$
$\text{trường hợp 1}$
\(\left[ \begin{array}{l}x-2>0\\3-x<0\end{array} \right.⇔ \) \(\left[ \begin{array}{l}x>2\\x>3\end{array} \right.⇒ x > 3\)
$\text{trường hợp 2}$
\(\left[ \begin{array}{l}x-2<0\\3-x>0\end{array} \right.⇔ \) \(\left[ \begin{array}{l}x<2\\x<3\end{array} \right.⇒ x <2\)
$\text{vậy 3 < x < 2}$
