Đáp án:
a) \(\% {V_{{O_2}}} = 21,05\% ;{\text{ \% }}{{\text{V}}_{C{O_2}}} = 26,32\% ;\% {V_{C{H_4}}} = 52,63\% \)
b) \(\% {m_{{O_2}}} = 25,2\% ;\;{\text{\% }}{{\text{m}}_{C{O_2}}} = 43,3\% ;\% {m_{C{H_4}}} = 31,5\% \)
c) \({d_{X/{H_2}}} = 13,37\)
Giải thích các bước giải:
Vì % số mol=% thể tích
\({n_{hh}} = 0,8 + 1 + 2 = 3,8{\text{ mol}}\)
\( \to \% {V_{{O_2}}} = \frac{{0,8}}{{3,8}} = 21,05\% ;{\text{ \% }}{{\text{V}}_{C{O_2}}} = \frac{1}{{3,8}} = 26,32\% \to \% {V_{C{H_4}}} = 52,63\% \)
\({m_{{O_2}}} = 0,8.32 = 25,6{\text{ gam; }}{{\text{m}}_{C{O_2}}} = 1.44 = 44{\text{ gam; }}{{\text{m}}_{C{H_4}}} = 2.16 = 32{\text{ gam}} \to {{\text{n}}_{hh}} = 25,6 + 44 + 32 = 101,6{\text{ gam}}\)
\( \to \% {m_{{O_2}}} = \frac{{25,6}}{{101,6}} = 25,2\% ;\;{\text{\% }}{{\text{m}}_{C{O_2}}} = \frac{{44}}{{101,6}} = 43,3\% \to \% {m_{C{H_4}}} = 31,5\% \)
\({M_X} = \frac{{{m_{hh{\text{X}}}}}}{{{n_{hh{\text{ X}}}}}} = \frac{{101,6}}{{3,8}} = 26,74 \to {d_{X/{H_2}}} = \frac{{26,74}}{2} = 13,37\)
