Đáp án:
Giải thích các bước giải:
$1/$
$Oxit$ $axit:$ $SO_3(lưu$ $huỳnh$ $đioxit)$
$Oxit$ $bazơ:$ $K_2O(kali$ $oxit)$
$CuO(đồng$ $(II)$ $oxit)$
$Mn_2O_7(mangan$ $heptoxit)$
$2/$
$a,S+O_2\buildrel{{t^o}}\over\longrightarrow$ $SO_2$
$b,3Fe+2O_2\buildrel{{t^o}}\over\longrightarrow$ $Fe_3O_4$
$c,4P+5O_2\buildrel{{t^o}}\over\longrightarrow$ $2P_2O_5$
$d,CH_4+2O_2\buildrel{{t^o}}\over\longrightarrow$ $CO_2+2H_2O$
$3/$
$a,PTPƯ:3Fe+2O_2\buildrel{{t^o}}\over\longrightarrow$ $Fe_3O_4$
$b,n_{Fe}=\frac{14}{56}=0,25mol.$
$Theo$ $pt:$ $n_{O_2}=\frac{2}{3}n_{Fe}=0,16mol.$
$⇒V_{O_2}=0,16.22,4=3,584l.$
$c,PTPƯ:2KClO_3\buildrel{{t^o}}\over\longrightarrow$ $2KCl+3O_2↑$
$Theo$ $pt:$ $n_{KClO_3}=\frac{2}{3}n_{O_2}=0,1mol.$
$⇒m_{O_2}=0,1.122,5=12,25g.$
chúc bạn học tốt!