p1 = 0,8 atm p2 = 4 atm
v1 = ———-> v2 = $\frac{v1}{2}$
T1 = 323°K T2 = ?
(1) -> (2):
$\dfrac{p1v1}{T1}$ = $\dfrac{p2v2}{T2}$
=> T2 = $\dfrac{p2v2T1}{v1p1}$
=> T2 = $\dfrac{4.\frac{1}{2}v1.323}{0,8v1}$
=> T2 = $\dfrac{646}{0,8}$
=> T2 = 807,5°K = 534,5°C