31)
nH2 = 0.5/2 = 0.25 mol
=> nhCl = 2nH2 = 0.5 mol
=> nCl = 0.5 mol
mCl = 17.75 (g)
mM = mkl + mCl = 8.3 + 17.75 = 26.05 g
32)
nH2 = 0.15 mol
Zn + 2HCl => ZnCl2 + H2
0.15___0.3_______0.15____0.15
mFeCl3 = 49.65 - 0.15*136 = 29.25 g
nFeCl3 = 0.18 mol
Fe2O3 + 6HCl => 2FeCl3 + 3H2O
0.09______0.36________0.18
nHCl = 0.66 mol
Vdd HCl = 0.66/0.5 = 1.32 (l)
mhh = 0.15*65 + 0.09*160 = 24.15 g