$n_{O_2}=16,8/22,4=0,75mol$
$C+O_2\overset{t^o}\to CO_2$
$S+O_2\overset{t^o}\to SO_2$
Gọi $n_C=a(mol);n_S=b(mol)$
Ta có :
$m_{hh}=12a+32b=14$
$n_{O_2}=a+b=0,75$
Ta có hệ pt :
$\left\{\begin{matrix}
12a+32b=14 & \\
a+b=0,75 &
\end{matrix}\right.$
$⇒\left\{\begin{matrix}
a=0,5& \\
b=0,25 &
\end{matrix}\right.$
$⇒m_C=0,5.12=6g$
$m_S=0,25.32=8g$