Đáp án:
\(\left\{ \begin{array}{l}
x = \frac{4}{3}\\
y = \frac{7}{9}
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
DK:x \ne \left\{ { - 1;0} \right\};y \ne 0\\
\left\{ \begin{array}{l}
\frac{{4x}}{{x + 1}} + \frac{x}{y} = 4\\
\frac{{4x}}{{x + 1}} + 8 = \frac{{6x}}{y}
\end{array} \right.\\
\to \left\{ \begin{array}{l}
\frac{x}{y} - 8 = 4 - 6.\frac{x}{y}\\
\frac{{4x}}{{x + 1}} + \frac{x}{y} = 4
\end{array} \right.\\
\to \left\{ \begin{array}{l}
7.\frac{x}{y} = 12\\
\frac{{4x}}{{x + 1}} + \frac{x}{y} = 4
\end{array} \right.\\
\to \left\{ \begin{array}{l}
y = \frac{7}{{12}}x\\
\frac{{4x}}{{x + 1}} + x.\frac{{12}}{{7x}} = 4
\end{array} \right.\\
\to \left\{ \begin{array}{l}
x = \frac{4}{3}\\
y = \frac{7}{9}
\end{array} \right.\left( {TM} \right)
\end{array}\)
