Đáp án:
$a) x=\{-1,0,1,2\}\\
b) x=\{-1,0,1,2,3,4,5\}$
Giải thích các bước giải:
$a)\frac{-5}{19}+\frac{3}{19}<\frac{x}{19}\leq \frac{13}{19}+\frac{-11}{19}\\
\Leftrightarrow 19.\left (\frac{-5}{19}+\frac{3}{19} \right )<19.\frac{x}{19}\leq 19.\left (\frac{13}{19}+\frac{-11}{19} \right )\\
\Leftrightarrow -5+3<x\leq 13-11\\
\Leftrightarrow -2<x\leq 2\\
\Rightarrow x=\{-1,0,1,2\}\\
b) \frac{-7}{8}+\frac{5}{6}\leq \frac{x}{24}\leq \frac{5}{8}+\frac{-5}{12}\\
\Leftrightarrow 24.\left (\frac{-7}{8}+\frac{5}{6} \right )\leq 24.\frac{x}{24}\leq 24.\left (\frac{5}{8}+\frac{-5}{12} \right )\\
\Leftrightarrow -21+20\leq x\leq 15-10\\
\Leftrightarrow -1\leq x\leq 5\\
\Rightarrow x=\{-1,0,1,2,3,4,5\}$
