I:
1,a
2,b
3,c
4,d
5,a,
6,a
7,b
8,c
II;
1:nhôm oxit
2,điphotpho pentaoxit
3,lưu huỳnh trioxit
4,sắt III oxit
bài 2:
1,4P+5O2=>2P2O5
2,KClO3=>KCl+$\frac{3}{2}$O2
3,Al+$\frac{3}{2}$ Cl2=>AlCl3
4,C2H4+3O2=>2CO2+2H2O
bai 3:
3Fe+2O2=>Fe3O4
mFe=25.2=>nFe=$\frac{25.2}{56}$=0.45(mol)
=>nO2=$\frac{0.45*2}{3}$= 0.3(mol)
=>Vo2=0.3*22.4=6.72(lít)
c,ta có PTHH:KClO3=>KCl+$\frac{3}{2}$O2
ta có nO2=0.3(mol)
=>nKClO3=$\frac{0.3*2}{3}$=0.2(mol)
=>mKClO3=0.2*122.5=24.5(g)
vậy.......................
