$10+2|x+3|=6
$→2|x+3|=4$
$→|x+3|=2$
$→\left[ \begin{array}{l}x+3=2\\x+3=-2\end{array} \right.$
$→\left[ \begin{array}{l}x=-1\\x=-5\end{array} \right.$
--
$22(x+2)=0$
$→x+2=0$
$→x=-2.$
--
$(2x+4)(x-5)=0$
$→\left[ \begin{array}{l}2x+4=0\\x-5=0\end{array} \right.$
$→\left[ \begin{array}{l}x=-2\\x=5\end{array} \right.$