Đáp án:
\(\frac{3}{7} < x < 8\)
Giải thích các bước giải:
\(\begin{array}{*{20}{l}}
{\left\{ {\begin{array}{*{20}{l}}
{\frac{{5 - x}}{4} < \frac{{3x + 1}}{2}}\\
{\left| {x - 3} \right| < 5}
\end{array}} \right.}\\
{ \to \left\{ {\begin{array}{*{20}{l}}
{5 > x - 3 > - 5}\\
{\frac{{5 - x - 6x - 2}}{4} < 0}
\end{array}} \right.}\\
{ \to \left\{ {\begin{array}{*{20}{l}}
{x > - 2}\\
{x < 8}\\
{ - 7x + 3 < 0}
\end{array}} \right.}\\
{ \to \left\{ {\begin{array}{*{20}{l}}
{ - 2 < x < 8}\\
{\frac{3}{7} < x}
\end{array}} \right.}
\end{array}\)
\(KL:\frac{3}{7} < x < 8\)
