$d_{hh/H_2}=18⇒M_{hh}=18.2=36⇒m_{hh}=0,1.36=3,6g$
$n_{hh}=2,24/22,4=0,1mol$
$PTHH :$
$C+O_2\overset{t^o}\to CO_2$
$ 2C+O_2\overset{t^o}\to 2CO$
Gọi $n_{CO}=a;n_{CO_2}=b(a,b>0)$
Ta có :
$n_{hh}=a+b=0,1$
$m_{hh}=44a+18b=3,6$
Ta có hpt :
$\left\{\begin{matrix}
a+b=0,1& \\
44a+18b=3,6 &
\end{matrix}\right.$
$⇔\left\{\begin{matrix}
a=0,05 & \\
b=0,05 &
\end{matrix}\right.$
Theo pt :
$n_{C(1)}=n_{CO_2}=0,05$
$n_{C(2)}=n_{CO}=0,05$
$⇒m_C=(0,05+0,05).12=1,2g$
$⇒m_{\text{than}}=1,2:95\%≈1,263g$
$n_{O_2(1)}=n_{CO_2}=0,05mol$
$n_{O_2(2)}=1/2.n_{CO}=1/2.0,05=0,025mol$
$⇒V_{kk}=(0,05+0,025).22,4.5=8,4l$
