\(\begin{array}{l}
1)\\
a)Fe + {H_2}S{O_4} \to FeS{O_4} + {H_2}\\
b)\\
nFe = \dfrac{{11,2}}{{56}} = 0,2\,mol\\
n{H_2}S{O_4} = \dfrac{{29,4}}{{98}} = 0,3\,mol\\
n{H_2}S{O_4}spu = 0,3 - 0,2 = 0,1\,mol\\
c)\\
n{H_2} = nFe = 0,2\,mol\\
V{H_2} = 0,2 \times 22,4 = 4,48l\\
d)\\
nFeS{O_4} = nFe = 0,2\,mol\\
mFeS{O_4} = 0,2 \times 152 = 30,4g\\
2)\\
a)\\
2Al + 6HCl \to 2AlC{l_3} + 3{H_2}\\
b)\\
nAl = \dfrac{{1,08}}{{27}} = 0,04\,mol\\
nHCl = \dfrac{{7,3}}{{36,5}} = 0,2\,mol\\
\dfrac{{0,04}}{2} < \dfrac{{0,2}}{6}\\
\Rightarrow nAlC{l_3} = nAl = 0,04\,mol\\
mAlC{l_3} = 0,04 \times 133,5 = 5,34g\\
c)\\
n{H_2} = 0,04 \times 1,5 = 0,06\,mol\\
ZnO + {H_2} \to Zn + {H_2}O\\
nZn = n{H_2} = 0,06\,mol\\
mZn = 0,06 \times 65 = 3,9g
\end{array}\)