Đáp án:
$\begin{array}{l}
d)\left( {\frac{2}{3}.x - \frac{1}{2}} \right).\frac{3}{4} - \frac{2}{3}x = 4\frac{1}{4}\\
\Rightarrow \frac{2}{3}.x.\frac{3}{4} - \frac{1}{2}.\frac{3}{4} - \frac{2}{3}x = \frac{{17}}{4}\\
\Rightarrow \frac{1}{2}x - \frac{2}{3}x = \frac{{17}}{4} + \frac{3}{8}\\
\Rightarrow \frac{{ - 1}}{6}x = \frac{{37}}{8}\\
\Rightarrow x = \frac{{37}}{8}.\left( { - 6} \right)\\
\Rightarrow x = - \frac{{111}}{4}
\end{array}$
Vậy $x = \frac{{ - 111}}{4}$
