1)
\(CuO + 2C{H_3}COOH\xrightarrow{{}}{(C{H_3}COO)_2}Cu + {H_2}O\)
\(C{H_3}COOH + NaOH\xrightarrow{{}}C{H_3}COONa + {H_2}O\)
\(2C{H_3}COOH + Mg\xrightarrow{{}}{(C{H_3}COO)_2}Mg + {H_2}\)
\({C_2}{H_4} + 3{O_2}\xrightarrow{{{t^o}}}2C{O_2} + 2{H_2}O\)
\(N{a_2}C{O_3} + 2C{H_3}COOH\xrightarrow{{}}2C{H_3}COONa + C{O_2} + {H_2}O\)
\({C_2}{H_4} + B{r_2}\xrightarrow{{}}{C_2}{H_4}B{r_2}\)
2)
Phản ứng xảy ra:
\(2C{H_3}COOH + ZnO\xrightarrow{{}}{(C{H_3}COO)_2}Zn + {H_2}O\)
Ta có:
\({m_{C{H_3}COOH}} = 200.6\% = 12{\text{ gam}} \to {{\text{n}}_{C{H_3}COOH}} = \frac{{12}}{{60}} = 0,2{\text{ mol}} \to {{\text{n}}_{ZnO}} = \frac{{0,2}}{2} = 0,1{\text{ mol}} \to {{\text{m}}_{ZnO}} = 0,1.(65 + 16) = 8,1{\text{ gam = a}}\)
