Giải thích các bước giải:
1.
\(\begin{array}{l}
Mg + {H_2}S{O_4} \to MgS{O_4} + {H_2}\\
MgO + {H_2}S{O_4} \to MgS{O_4} + {H_2}O\\
{n_{{H_2}}} = 0,01mol \to {n_{Mg}} = {n_{{H_2}}} = 0,01mol\\
\to {m_{Mg}} = 0,01 \times 24 = 0,24\\
\to \% {m_{Mg}} = \dfrac{{0,24}}{{1,04}} \times 100\% = 23,08\% \\
\to {m_{MgO}} = 1,04 - 0,24 = 0,8g\\
\to \% {m_{MgO}} = \dfrac{{0,8}}{{1,04}} \times 100\% = 76,92\%
\end{array}\)
2.
\(\begin{array}{l}
Mg + 2{H_2}S{O_4} \to MgS{O_4} + 2{H_2}O + S{O_2}\\
MgO + {H_2}S{O_4} \to MgS{O_4} + {H_2}O\\
{n_{S{O_2}}} = 0,01mol\\
\to {n_{Mg}} = {n_{S{O_2}}} = 0,01mol\\
\to {m_{Mg}} = 0,01 \times 24 = 0,24\\
\to \% {m_{Mg}} = \dfrac{{0,24}}{{1,04}} \times 100\% = 23,08\% \\
\to {m_{MgO}} = 1,04 - 0,24 = 0,8g\\
\to \% {m_{MgO}} = \dfrac{{0,8}}{{1,04}} \times 100\% = 76,92\%
\end{array}\)
