$C_6H_{12}O_6 \buildrel{{\text{men rượu}}}\over\to 2C_2H_5OH+ 2CO_2$
$C_2H_5OH+ O_2 \buildrel{{\text{men giấm}}}\over\to CH_3COOH+ H_2O$
$CH_3COOH+ C_2H_5OH \buildrel{{t^o, H_2SO_4}}\over\rightleftharpoons CH_3COOC_2H_5+ H_2O$
$2CH_3COOH+ CuO \to (CH_3COO)_2Cu+ H_2O$
$CH_3COOH+ NaOH \to CH_3COONa+ H_2O$