Đáp án:
Giải thích các bước giải:
a) $C2H4+Br2-->C2H4Br2$
$nBr2=0,56/160=0,0035(mol)$
$nC2H4=nBr2=0,0035(mol)$
=>$V_{C2H4}=0,003.22,4=0,0784(l)$
=>%$V_{C2H4}=0,0784/1,12.100$%$=7%$
=>%$VCH4=100-7=93$%
b)
$CH4+2O2-to->CO2+2H2O$
$C2H4+3O2-->2CO2+2H2O$
$nCO2=nCH4=0,0053(mol)$
$nCH4=1,12-0,0784/22,4=0,0465(mol)$
=>$nCO2=2nC2H4=0,093(mol)$
=>$nCO2=0,093+0,0035=0,0965(mol)$
$CO2+Ca(OH)2-->CaCO3+H2O$
$nCaCO3=nCO2=0,0965(mol)$
=>$mCaCO3=0,0965.100=9,65(g)$