a) |$\frac{3}{4}$ -2x|+$\frac{1}{6}$ =$\frac{9}{2}$
⇔|$\frac{3}{4}$-2x| = $\frac{9}{2}$ - $\frac{1}{6}$
⇔|$\frac{3}{4}$ -2x|=$\frac{13}{3}$
⇔\(\left[ \begin{array}{l}\frac{3}{4}- 2x=\frac{13}{3} \\\frac{3}{4}- 2x=\frac{-13}{3}\end{array} \right.\)
⇔\(\left[ \begin{array}{l}2x=\frac{-43}{12} \\2x=\frac{61}{12}\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=\frac{-43}{24} \\x=\frac{61}{24} \end{array} \right.\)
b) $\frac{3}{2}$.x=$\frac{1}{2}$.x+$\frac{15}{12}$
⇔$\frac{3}{2}$.x - $\frac{1}{2}$.x = $\frac{15}{12}$
⇔ x= $\frac{15}{12}$
