$\text{Câu 10:}$
`f, 3/2 (x+5)-(7/2 - x) = 0`
`⇔ 3/2 x + 15/2 - 7/2 + x = 0`
`⇔ (3/2x + x)+(15/2 - 7/2)=0`
`⇔ 5/2 x + 4 = 0`
`⇔ 5/2 x = -4`
`⇔ x = -8/5`
$\text{Vậy}$ `x = -8/5` $\text{là nghiệm của đa thức}$ `3/2 (x+5)-(7/2-x)`
`g, x² - 7x + 6 = 0`
`⇔ x² - 6x - x + 6 = 0`
`⇔ x(x-6)-(x-6)=0`
`⇔ (x-1)(x-6)=0`
\(⇒ \left[ \begin{array}{l}x-1=0\\x-6=0\end{array} \right.\)
\(⇒ \left[ \begin{array}{l}x=1\\x=6\end{array} \right.\)
$\text{Vậy...}$
