$|4x-\dfrac{2}{3}|=\dfrac{1}{5}$
TH1: $4x-\dfrac{2}{3}=\dfrac{1}{5}$
$4x=\dfrac{13}{15}$
$x=\dfrac{13}{60}$
TH2: $4x-\dfrac{2}{3}=-\dfrac{1}{5}$
$4x=\dfrac{7}{15}$
$x=\dfrac{7}{60}$
Vậy $x\in\bigg\{\dfrac{13}{60};\dfrac{7}{60}\bigg\}$
$-6x+\dfrac{1}{2}=-10x-\dfrac{3}{5}+\dfrac{1}{4}$
$-6x+10x=\dfrac{-3}{5}+\dfrac{1}{4}-\dfrac{1}{2}$
$4x=\dfrac{-17}{20}$
$x=\dfrac{-17}{20}:4$
$x=\dfrac{-17}{20}\cdot\dfrac{1}{4}$
$x=\dfrac{-17}{80}$
Vậy $x=\dfrac{-17}{80}$
