Đáp án:
$-\sin^232^{\circ}$
Giải thích các bước giải:
$\dfrac{\sin(-328^{\circ}).\sin958^{\circ}}{\cot 572^{\circ}}\\=\dfrac{\sin(32^{\circ}-2.180^{\circ}) .\sin(58^{\circ}+5.180^{\circ})}{\cot (32^{\circ}+3.180^{\circ})}\\
=\dfrac{-\sin32^{\circ}.\sin58^{\circ}}{\cot 32^{\circ}}\\
=\dfrac{-\sin32^{\circ}.\cos32^{\circ}}{\cot 32^{\circ}}\\
=\dfrac{-\sin32^{\circ}.\cos32^{\circ}}{\dfrac{\cos 32^{\circ}}{\sin 32^{\circ}}}\\
=-\sin^232^{\circ}$
