Đáp án:
$e)
\dfrac{45}{2}$
Giải thích các bước giải:
$e)
\left [ 6+\left ( \dfrac{1}{2} \right )^3-\left | -\dfrac{1}{2} \right | \right ]:\dfrac{3}{12}\\
=\left [ 6+ \dfrac{1}{8}-\dfrac{1}{2} \right ]:\dfrac{3}{12}\\
=\left [ \dfrac{48}{8}+ \dfrac{1}{8}-\dfrac{4}{8} \right ]:\dfrac{3}{12}\\
=\dfrac{45}{8}.\dfrac{12}{3}\\
=\dfrac{45}{2}$