Đáp án:
d. \(\left[ \begin{array}{l}
x = - \frac{1}{2}\\
x = \frac{4}{9}
\end{array} \right.\)
Giải thích các bước giải:
\(\begin{array}{l}
a.\left| {8x} \right| = 3x + 2\\
\to \left[ \begin{array}{l}
8x = 3x + 2\\
8x = - 3x - 2
\end{array} \right.\\
\to \left[ \begin{array}{l}
5x = 2\\
11x = - 2
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = \frac{2}{5}\\
x = - \frac{2}{{11}}
\end{array} \right.\\
b.\left| {x - 5} \right| = 5x - 1\\
\to \left[ \begin{array}{l}
x - 5 = 5x - 1\\
x - 5 = - 5x + 1
\end{array} \right.\\
\to \left[ \begin{array}{l}
4x = - 4\\
6x = 6
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = - 1\\
x = 1
\end{array} \right.\\
c.\left| {6x} \right| = 2x + 12\\
\to \left[ \begin{array}{l}
6x = 2x + 12\\
6x = - 2x - 12
\end{array} \right.\\
\to \left[ \begin{array}{l}
4x = 12\\
8x = - 12
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = 3\\
x = - \frac{3}{2}
\end{array} \right.\\
d.\left| {x - 4} \right| = 3x - 5\\
\to \left[ \begin{array}{l}
x - 4 = 3x - 5\\
x - 4 = - 3x + 5
\end{array} \right.\\
\to \left[ \begin{array}{l}
2x = - 1\\
4x = 9
\end{array} \right.\\
\to \left[ \begin{array}{l}
x = - \frac{1}{2}\\
x = \frac{4}{9}
\end{array} \right.
\end{array}\)
