Đáp án:
a) 20%
b) 2,24M
Giải thích các bước giải:
\(\begin{array}{l}
a)\\
m{H_2}S{O_4} = 20 \times 50\% = 10g\\
C\% dd{H_2}S{O_4} = \dfrac{{10}}{{50}} \times 100\% = 20\% \\
b)\\
Vdd{H_2}S{O_4} = \dfrac{{50}}{{1,1}} = \dfrac{{500}}{{11}}\,ml = \dfrac{1}{{22}}(l)\\
n{H_2}S{O_4} = \dfrac{{10}}{{98}} = \dfrac{5}{{49}}mol\\
{C_M}{H_2}S{O_4} = \dfrac{{\dfrac{5}{{49}}}}{{\dfrac{1}{{22}}}} = 2,24M
\end{array}\)