1/
$n_{CuSO_4}=\dfrac{8}{160}=0,05mol.$
$⇒CM_{CuSO_4}=\dfrac{0,05}{0,1}=0,5M.$
2/
$PTPƯ:C+O_2\xrightarrow{t^o} CO_2$
$n_{C}=\dfrac{32}{12}=\dfrac{8}{3}mol.$
$n_{CO_2}=\dfrac{54}{44}=\dfrac{27}{22}mol.$
$\text{Lập tỉ lệ:}$ $\dfrac{\frac{8}{3}}{1}>\dfrac{\frac{27}{22}}{1}$
$⇒n_{C}$ $dư.$
$Theo$ $pt:$ $n_{O_2}=n_{CO_2}=\dfrac{27}{22}mol.$
$⇒m_{O_2}=\dfrac{27}{22}.32=39,27g.$
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