a) PTHH: 2Na+2C2H5OH→2C2H5ONa+H2↑
0,167 0,0835
2Na+2H2O→2NaOH+H2↑
0,022 0,011
b) Vrượu=$\frac{96.10}{100}$=9,6(ml)
=>Vnước=10-9,6=0,4(ml)
mà Drượu=0,8g/ml
=>mC2H5OH=D.V=0,8.9,6=7,68(g)
c) nC2H5OH=7,68/46≈0,167(mol)
Dnước=1g/ml
mH2O=V.D=0,4.1=0,4(g)
=>nH2O=0,4/18≈0,022 (mol)
theo pt=>nH2=0,0835+0,011=0,0945(mol)
=>VH2=0,0945.22,4≈2,117(l)
