Giải thích các bước giải:
\(\begin{array}{l}
NaOH + C{H_3}{\rm{COO}}H \to C{H_3}{\rm{COO}}Na + {H_2}O\\
{m_{NaOH}} = \dfrac{{30 \times 20\% }}{{100\% }} = 6g\\
\to {n_{NaOH}} = 0,15mol\\
\to {n_{C{H_3}{\rm{COO}}H}} = {n_{NaOH}} = 0,15mol\\
\to C{M_{C{H_3}{\rm{COO}}H}} = \dfrac{{0,15}}{{0,5}} = 0,3M\\
2C{H_3}{\rm{COO}}H + N{a_2}C{O_3} \to 2C{H_3}{\rm{COO}}Na + {H_2}O + C{O_2}\\
{n_{N{a_2}C{O_3}}} = 0,2 \times 0,5 = 0,1mol\\
\to {n_{C{H_3}{\rm{COO}}H}} > {n_{N{a_2}C{O_3}}} \to {n_{C{H_3}{\rm{COO}}H}}dư\\
\to {n_{C{O_2}}} = {n_{N{a_2}C{O_3}}} = 0,1mol\\
\to {V_{C{O_2}}} = 0,1 \times 22,4 = 2,24l
\end{array}\)
