PTHH: Zn + 2HCl → ZnCl2 + H2↑
0,1 0,2 0,1 0,1 (mol)
100ml=0,1l
nHCl=CM.V=2.0,1=0,2(mol)
mZn=n.M=0,1.65=6.5(g)
VH2(đktc)=n.22,4=0,1.22,4=2,24(l)
mZnCl2=n.M=0,1.136=13,6(g)
mddZnCl2=mZn+mddHCl-mH2
=0,1.65+100.1,1-0,1.2=116,3(g)
C%ddZnCl2=$\frac{mct}{mdd}$ .100%≈11.7%