$ m , $
$ \dfrac{-2}{3} - \dfrac{1}{3} ( 2x - 5 ) = \dfrac{3}{2}$
$\dfrac{1}{3} ( 2x - 5 ) = \dfrac{-2}{3} - \dfrac{3}{2}$
$\dfrac{1}{3} ( 2x - 5 ) = \dfrac{-13}{6}$
$( 2x - 5 ) = ( -6 )$
$2x = -1$
$x = -0,5$
$n,$
$( 3x - 1 ) ( -\dfrac{1}{2}x + 5 ) = 0$
$= ( 3x . x ) ( -\dfrac{1}{2} + 5 - 1 ) = 0$
$( 3x^2 ) = 0 $
$-> x = 0$