Đáp án:
$a/$
C2H5OH + Na --> C2H5ONa + 1/2H2
x x x 1/2x
C6H5OH + Na --> C6H5ONa + 1/2H2
y y y 1/2y
C6H5OH + 3Br2 --> C6H2Br3OH ↓ + 3HBr
y 3y y 3y
$b/$
$nH2 = 3,36/22,4 = 0,15 (mol)$
Ta có:
$\left \{ {{46x + 94y = 18} \atop {1/2x + 1/2y = 0,15}} => \right.$ $\left \{ {{x=0,2125} \atop {x=0,0875}} \right.$
$mC6H2Br3OH = 0,0875.331 = 28,9625 (g)$