$n_{Zn}=13/65=0,2 mol$
$PTHH : Zn+H_2SO_4\to ZnSO_4+H_2$
Theo pt :
$n_{H_2}=n_{H_2SO_4}=n_{ZnSO_4}=0,2mol$
$a/V_{H_2}=0,2.22,4=4,48l$
$b/m_{H_2SO_4}=0,2.98=19,6g$
$c/m_{ZnSO_4}=0,2.161=32,2g$
$d/m_{ddH_2SO_4}=\dfrac{19,6}{19,6\%}=100g$
$m_{ddspu}=13+100-0,2.2=112,6g$
$⇒C\%_{ZnSO_4}=\dfrac{32,2}{112,6}.100\%=25,6\%$