Đáp án:
C2H6O
Giải thích các bước giải:
\(\begin{array}{l}
7)\\
{C_2}{H_2} + {H_2} \xrightarrow{t^0,xt} {C_2}{H_4}\\
{C_2}{H_4} + {H_2}O \xrightarrow{t^0,xt} {C_2}{H_5}OH\\
{C_2}{H_5}OH + {O_2} \xrightarrow{lên men} C{H_3}COOH + {H_2}O\\
2C{H_3}COOH + CuO \to {(C{H_3}COO)_2}Cu + {H_2}O\\
8)\\
a)\\
nC{O_2} = \dfrac{m}{M} = \dfrac{{44}}{{44}} = 1\,mol\\
n{H_2}O = \dfrac{m}{M} = \dfrac{{27}}{{18}} = 1,5\,mol\\
mO = 23 - 1 \times 12 - 1,5 \times 2 = 8g\\
nO = \dfrac{m}{M} = \dfrac{8}{{16}} = 0,5\,mol\\
nC:nH:nO = 1:3:0,5 = 2:6:1\\
\Rightarrow CTDGN:{C_2}{H_6}O\\
MA = 46g/mol \Rightarrow 46n = 46 \Rightarrow n = 1\\
\Rightarrow CTPT:{C_2}{H_6}O\\
b)\\
C{H_3} - C{H_2} - OH
\end{array}\)
