Đáp án:
Bài 1:
\[TT1:\left\{ \begin{array}{l}
{T_1} = 273K\\
{p_1} = 1atm\\
{V_1} = 0,5l
\end{array} \right.\]
\[TT2:\left\{ \begin{array}{l}
{T_2} = 546K\\
{p_2} = 2atm\\
{V_2} = 0,5l
\end{array} \right.\]
\[TT3:\left\{ \begin{array}{l}
{T_3} = 546K\\
{p_3} = \frac{5}{{56}}atm\\
{V_3} = 11,2l
\end{array} \right.\]
Bài 2:
\[{p_3} = {3.10^5}\]
Giải thích các bước giải:
Bài 1:
\(\begin{array}{l}
TT1:\left\{ \begin{array}{l}
{T_1} = 273K\\
{p_1} = 1atm\\
{V_1} = 0,5l
\end{array} \right.\\
QT1:\dfrac{{{p_1}}}{{{T_1}}} = \dfrac{{{p_2}}}{{{T_2}}} \Rightarrow \dfrac{1}{{273}} = \dfrac{2}{{{T_2}}} \Rightarrow {T_2} = 546K\\
TT2:\left\{ \begin{array}{l}
{T_2} = 546K\\
{p_2} = 2atm\\
{V_2} = 0,5l
\end{array} \right.\\
QT2:{p_2}{V_2} = {p_3}{V_3} \Rightarrow 2.0,5 = {p_3}.11,2 \Rightarrow {p_3} = \dfrac{5}{{56}}atm\\
TT3:\left\{ \begin{array}{l}
{T_3} = 546K\\
{p_3} = \frac{5}{{56}}atm\\
{V_3} = 11,2l
\end{array} \right.
\end{array}\)
Bài 2:
\(\begin{array}{l}
TT1:\left\{ \begin{array}{l}
{T_1} = 300K\\
{p_1} = {10^5}Pa\\
{V_1} = 10l
\end{array} \right.\\
QT1:{p_1}{V_1} = {p_2}{V_2} \Rightarrow {10^5}.10 = {2.10^5}.{V_2} \Rightarrow {V_2} = 5l\\
TT2:\left\{ \begin{array}{l}
{T_2} = 300K\\
{p_2} = {2.10^5}Pa\\
{V_2} = 5l
\end{array} \right.\\
QT2:\dfrac{{{p_3}}}{{{T_3}}} = \dfrac{{{p_2}}}{{{T_2}}} \Rightarrow \dfrac{{{p_3}}}{{177 + 273}} = \dfrac{{{{2.10}^5}}}{{300}} \Rightarrow {p_3} = {3.10^5}
\end{array}\)