ĐKXĐ của A là :
`1-16x^2>0`
⇔`(1-4x)(1+4x)>0`
⇔\(\left[ \begin{array}{l}\left \{ {{1-4x>0} \atop {1+4x>0}} \right.\\\left \{ {{1-4x<0} \atop {1+4x<0}} \right.\end{array} \right.\)
⇔\(\left[ \begin{array}{l}\left \{ {{x<\frac{1}{4}} \atop {x>\frac{-1}{4}}} \right.\\\left \{ {{x>\frac{1}{4}} \atop {x<\frac{-1}{4}}} \right.\end{array} \right.\)
⇔`1/4>x> - 1/4`
ĐKXĐ của B là :
`x^2-3>0`
⇔`(x-\sqrt3 )(x+\sqrt3)>0`
⇔\(\left[ \begin{array}{l}\left \{ {{x-\sqrt3>0} \atop {x+\sqrt3>0}} \right.\\\left \{ {x-\sqrt3{<0} \atop {x+\sqrt3<0}} \right.\end{array} \right.\)
⇔\(\left[ \begin{array}{l}\left \{ {{x>\sqrt3} \atop {x>-\sqrt3}} \right.\\\left \{ {x<\sqrt3{} \atop {x<-\sqrt3}} \right.\end{array} \right.\)
⇔ \(\left[ \begin{array}{l}x>\sqrt3\\x<-\sqrt3\end{array} \right.\)
⇔`x>\sqrt3` hoặc `x<-\sqrt3`
