Đáp án:
$\begin{array}{l}
Do:co{s^2}x - {\sin ^2}x = \cos 2x\\
\Rightarrow \sin x.\cos x = {\cos ^2}x - {\sin ^2}x\\
\Leftrightarrow \frac{1}{2}.2.\sin x.\cos x = \cos 2x\\
\Leftrightarrow \frac{1}{2}.\sin 2x = \cos 2x\\
\Leftrightarrow \tan 2x = 2\\
\Leftrightarrow 2x = \arctan 2 + k\pi \\
\Leftrightarrow x = \dfrac{1}{2}.\arctan 2 + \dfrac{{k\pi }}{2}
\end{array}$