Câu 22: B
R2CO3+2HCl→2RCl+CO2+H2O
⇒nR2CO3=nCO2=0,005mol
⇒MR2CO3=0,0050,53=106=2R+60
⇔R=23(Na)
Câu 23: B
A2Ox+2xHCl→2AClx+xH2O
nA2Ox=2A+16x7,2
⇒nAClx=2nA2Ox=2A+16x14,4
⇒2A+16x14,4=A+35,5x12,7
⇔12,7(2A+16x)=14,4(A+35,5x)
⇔A=28x
x=2⇒A=56(Fe)
Câu 24: A
C2H4+Br2→C2H4Br2
nC2H4=nBr2=0,05mol
%VC2H4=1,680,05.22,4.100=66,67%