$\text { Đáp án: }$
$\text { Ta có đk: }$ ` 2x - 3 ≥ 0 ` ` <=> ` ` 2x ≥ 3 ` ` <=> ` ` x ≥ \frac{3}{2} `
` |x + 5| = 2x - 3 `
` => ` \(\left[ \begin{array}{l}x+5=2x-3\\x+5=–(2x-3)\end{array} \right.\)
` => ` \(\left[ \begin{array}{l}x-2x=-3-5\\x+5=–2x+3\end{array} \right.\)
` => ` \(\left[ \begin{array}{l}–x=–8\\x+2x=3-5\end{array} \right.\)
` => ` \(\left[ \begin{array}{l}x=8\\3x=-2\end{array} \right.\)
` => ` \(\left[ \begin{array}{l}x=8\\x=\frac{-2}{3}(loại)\end{array} \right.\)
$\text { Vậy }$ ` S = { 8 } `
